Find the length of median AD if vertices are A(1,-1),B(-4,6) and C(-3,-5).
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d(x)=-3+(-4)/2
d(x)=-7/2
d(y)=-5+6/2=1/2
ad^2=(-7/2-1)+(1/2+1)
ad^2=(-9/2)+3/2
ad^2=-6/2=-3
ad=√3units
I hope it help you
d(x)=-7/2
d(y)=-5+6/2=1/2
ad^2=(-7/2-1)+(1/2+1)
ad^2=(-9/2)+3/2
ad^2=-6/2=-3
ad=√3units
I hope it help you
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