Find the length of median ad if vertices are a 1, - 1 b - 46 and c - 3, - 5
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Answer:
√17/2 units
Step-by-step explanation:
median AD divides BC into two equal lengths
BD= DC
D(x,y)
D is the midpoint of BC
by midpoint formula:
x= x1+x2/2 = -4 -3 /2
x= -7/2
y= y1+y2/2 = 6-5/2
y= 1/2
D(-7/2 , 1/2)
length of AD=
√(x2-x1)² + (y2-y1)²
= √(-7/2 -1)² + (1/2 +1)²
= √(-7-2/2)² + (1+2/2)²
= √ (-5/2)² + (3/2)²
=√ (25/4) + (9/4)
=√ (25+9/4)
=√ (34/4)
= √ 17/2 units
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