Question

Find the length of median BD of ∆ ABC, if A(7,–3), B(5,3) and C(3,1)

Answer 1

Answer:

hope this helps u.............

Answer 2

Answer:

The length of BD = 4 √2

Step-by-step explanation:

A ( 7 , -3) & B( 5 , 3) & C ( 3 , 1 )

By using distance formula

AB = $\sqrt{(x_{1}- x_{2} )^{2} + (y_{1}- y_{2} )^{2} } = \sqrt{( 7 - 5)^{2} + ( -3 -3)^{2} } = \sqrt{4 +36} = \sqrt{40}$

AC =  $\sqrt{(x_{1}- x_{2} )^{2} + (y_{1}- y_{2} )^{2} } = \sqrt{( 7 - 3)^{2} + ( -3 -1)^{2} } =\sqrt{16 +16} =\sqrt{32}$

AD = $\frac{AC}{2}$                 ( BD is median )

Now by using pythagoras theoram in Δ ABD,

BD =  $\sqrt{AB^{2} - AD^{2} } = \sqrt{40 - \frac{32}{4} } = \frac{8\sqrt{2} }{2}$

∴ The length of BD = 4 √2