Question

find the length of perpendicular drawn from point (1,2) to the line 4x+3y-1=0



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Answer 1

Answer:

The answer is $\frac{9}{5}$

Step-by-step explanation:

Concept :

Perpendicular distance of the point P$(x_1,y_1)$ from the line $ax+by+c=0$ is given by $|\frac{ax_1+by_1+c}{\sqrt{a^2+b^2}}|$

Therefore the perpendicular distance of (1,2) from the line $4x+3y-1=0$ is

                                    $=|\frac{4(1)+3(2)-1}{\sqrt{4^2+3^2}}|=\frac{4+6-1}{\sqrt {25}}=\frac{9}{5}$