Question

Find the length of seconds pendulum at a place where g = 10 ms-2

Answer 1

The answer is 10m aprox (=0.993)

Which is detailed in the attachment

HOPE IT WOULD BE HELPFULL

Answer 2

Length of the pendulum is 10.13 m

Given:

$g = 10 \ ms^{-2}$

Solution:

The length of seconds pendulum at a place is to be calculated,

We will apply the formula of Time period,

$T=\frac{2 \pi \sqrt{l}}{g}$

Second pendulum oscillates with a time period of 2 seconds.  

Thereby putting the values, we have,

$\Rightarrow 2=\frac{2 \pi \sqrt{l}}{10}$

Squaring both sides we have,

$4=T=\frac{4 \pi l}{100}$

$l=\frac{4 \times 100}{4 \times 3.14 \times 3.14}$

$l=\frac{400}{39.43}$

$l = 10.13 \ m$