find the length of side of a square of side (2x-3) cm and whose perimeter is 68 cm?
Answers
Answered by
2
Answer:
perimeter of square = 4a
68 = 4(2x-3)
68 = 8x-12
56= 8x
x= 56/8
x= 7
length = (2x-3)
= (2*7-3)
= (14-3)
= 11 cm
Answered by
0
Answer:
17
Step-by-step explanation:
68=4(2x-3)
68=8x-12
8x=68+12
8x=80
x=80/8
x=10
Length=(2x-3)
Now put the value of x
(2*10-3)
(20-3)
length=17
Check
17*4=68
Similar questions