Math, asked by pratham7532, 1 year ago

find the length of the arc of a circle of radius 25 CM subtending a central angle of 15 degree

Answers

Answered by SupriyaGalanki
4
I hope it will help you
Attachments:
Answered by Anonymous
11

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
6

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
6

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
6

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
5

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
5

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
5

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
5

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
5

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
5

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
5

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
5

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
5

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
5

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Answered by Anonymous
5

Answer:

Length of Arc = (∅/360) x 2πr

∅ = L x 360/2πr

= 15 x 360/(2π x 25) degrees

= 15 x 360 x 7/(2 x 22 x 25) degrees

= 34.36°

= 34.36 x π/180 ≈ 0.6 radians

:-)

# ItzYourDreamGirl

Similar questions