find the length of the chord,which is at a distance of 3 cm from the centre of a circle of radius 5 cm
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Draw a perpendicular from centre O to the chord AB . so according to theorem, the chord gets bisected.
Name the point of intersection of AB and perpendicular bisector as C.
triangle BOC is a right angle triangle
OC = 3cm (distance) ( perpendicular )
OB = 5 cm ( radius) ( hypotenuse )
So,
OB2 = OC2 + BC2
25 - 9 = 16 = BC2
root 16 = 4
So,
AC = BC = 4cm
AB = 8 cm
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