Question

find the length of the chord which is at the distance of 3 centimetre from the centre of circle

Answer 1

draw a perpendicular from chord let it be as centre o and chord AB. and it be perpendicular at point c.
.

.
so triangle BOC is a right angle triangle.
OC is 3 cm
and OB is 5 cm as it is hypotenuse.
.
OB^2= OC^2 + BC^2
.SUBSTITUTE THE VALUE..
.then it is 4.
.
so AC=BC =4
.
AB =8

Answer 2

join any one end of the chord to the centre. It will be equal to the radius = 5 cm.

Now the height = perpendicular and the radius will be Hypotenuse. WE HAVE TO FIND THE BASE.

(H)^2 = (P)^2 + (B)^2
= > H^2- P^2 = B^2
= 5^2 - 3^2 = B ^2
= 25 - 9 = B^2
= 16 = B^2

So B = root 16 = 4 cm.

now for getting the length of the whole chord we will multiply that by 2 because B = 1/2 of the L. of chord.........( perpendicular from centre devides the chord into 2 equal parts.)

So, l. of chord = 2× B = 2× 4 = 8 cm.

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