Find the length of the chord which is not at a distance of 3cm from the Centre of the circle of the radius 5cm
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Answer is 8cm applying Pythagoras theorem
radius bisects the chord so radius would become hypotenuse and the distance would be a side
and you know the other side would be 4 cm so the chord would be double of that that is 8 cm
radius bisects the chord so radius would become hypotenuse and the distance would be a side
and you know the other side would be 4 cm so the chord would be double of that that is 8 cm
Answered by
3
Answer:
Given that:-
- Radius of the Circle, (r) = 5 cm
- Distance of the chord from the centre = 3 cm
To find:-
- Length of the chord
Formula to be used :-
- Pythagoras theorem
Solution:
- Let AOC is a right angled triangle.
By Using Pythagoras theorem, we get
⇒ AO² + OC² = AC²
⇒ 3² + OC² = 5²
⇒ 9 + OC² = 25
⇒ OC² = 25 - 9
⇒ OC² = 16
⇒ OC = 4
Length of the chord = 4 + 4 = 8 cm.
Hence,
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