Find the length of the curve y = 3 + 2 from (0, 3) to (2, 4).
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go kfdvjjyhv. jjilmbxdaf
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√(3-0)²+(4-2)²
=√9+4
=√13
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Similar questions
=
4√6−2√3
Explanation:
Length, s, is:
s=∫30√1+(y')2dx
y'=(x+2)12
⇒s=∫30√3+xdx
=[23(3+x)32]30
=23(632−332)
=4√6−2√3