Question

Find the length of the daigonal of a rectangle ABCD whose sides are 15cm and 8cm​

Answer 1

HeYa❤️...

Answer:

Diagonal of rectangle ABCD= BD.

By Pythagoras Theorem,

$bd {}^{2} = bc {}^{2} + cd {}^{2} \\ \\ bd {}^{2} = (8) {}^{2} + (15) {}^{2} \\ \\ bd {}^{2} = 289cm$

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Answer 2

Explanation:

Hola ! mates here's Ur solution...

Given:

BC = 15cm.

CD = 8 cm.

Find; BD the diagonal.

Solution:

and, we know that all the angles of rectangle is 90°.

so, <C = 90..

Now, by Pythagoras theorem:

In ∆ BCD ;

BC ² + CD² = BD²

= 15² + 8² = BD²

= 225+64= BD²

= 289= BD ²

= BD = √289= 17cm.(ans)...

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