Question

find the length of the diagonal of a rectangle whose sides are 6 and 4 cm.​

Answer 1

Step-by-step explanation:

Let the diagnol be x

(x)^2 = (6)^2 + (4)^2 [Pythagoras theorem]

x^2 = 36+16

x^2 = 53

x = √52 cm

Hope this helps

MARK AS BRAINLIEST

Answer 2

$h2 = p2 + b2 \\ h2 = 36 + 16 \\ = 52 \\ h2 = 7</strong><strong>.</strong><strong>2cm \\ \\ i \: hope \: it \: help \: you$