Question

Find the length of the diagonal of a rectangle whose sides are 15 cm and 8 cm.

Answer 1

Length=15cmand breadth=8cm
Lenght of diagonal=$\sqrt{l^2+b^2$
therfore=$\sqrt{ 15^2+8^2$
=$\sqrt{289$=17
Therfore length of the diagonal =17

Answer 2

Answer:

Diagonal of the rectangle (d)=17cm

Explanation:

Given Dimensions of a rectangle:

Length (l) = 15 cm

Breadth (b) = 8 cm

Let diagonal = d

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We know that,

$\boxed {Diagonal (d)=\sqrt{l^{2}+b^{2}}}$

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$\implies d = \sqrt{(15)^{2}+8^{2}}$

$\implies d = \sqrt{225+64}$

$\implies d = \sqrt{289}$

$\implies d = \sqrt{17^{2}}$

$\implies d = 17\: cm$

Therefore,

Diagonal of the rectangle (d)=17cm

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