Question

Find the length of the diagonal of a rectangle with sides 8cm and 6cm​

Answer 1

Answer:

8²+6²= ad²

64+36=ad²

100=ad²

√100=ad

10=ad

adis the diagonal

Answer 2

Answer:

10

Step-by-step explanation:

Step-by-step explanation:Let the diagonal of rectangle be ABC

Step-by-step explanation:Let the diagonal of rectangle be ABCAC^2=AB^2+BC^2 (Pythagoras Theorem)

Step-by-step explanation:Let the diagonal of rectangle be ABCAC^2=AB^2+BC^2 (Pythagoras Theorem)AC^2=8^2+6^2

Step-by-step explanation:Let the diagonal of rectangle be ABCAC^2=AB^2+BC^2 (Pythagoras Theorem)AC^2=8^2+6^2AC^2=64+36

Step-by-step explanation:Let the diagonal of rectangle be ABCAC^2=AB^2+BC^2 (Pythagoras Theorem)AC^2=8^2+6^2AC^2=64+36AC^2=100

Step-by-step explanation:Let the diagonal of rectangle be ABCAC^2=AB^2+BC^2 (Pythagoras Theorem)AC^2=8^2+6^2AC^2=64+36AC^2=100AC=10 (Taking square roots)

Step-by-step explanation:Let the diagonal of rectangle be ABCAC^2=AB^2+BC^2 (Pythagoras Theorem)AC^2=8^2+6^2AC^2=64+36AC^2=100AC=10 (Taking square roots)

Step-by-step explanation:Let the diagonal of rectangle be ABCAC^2=AB^2+BC^2 (Pythagoras Theorem)AC^2=8^2+6^2AC^2=64+36AC^2=100AC=10 (Taking square roots) Hope you understand

Step-by-step explanation:Let the diagonal of rectangle be ABCAC^2=AB^2+BC^2 (Pythagoras Theorem)AC^2=8^2+6^2AC^2=64+36AC^2=100AC=10 (Taking square roots) Hope you understand Plzzzz Mark it as Brainliest Answer