Question

Find the length of the height of an equilateral triangle of dide 24 cm . (take
$\sqrt{3}$
​

Answer 1

equilateral triangle be h cm.

Then,

Area of the triangle =

2

1

×

base×

height

=

(

2

1

×

24×

h)cm

2

Let the side of the equilateral triangle be a cm

Area of the equilateral triangle

=

4

3

×

(a)

2

sq.Units

=

4

3

×

24×

24

=

(

3

×

144)cm

2

∴

(

2

1

×

24×

h)=

(

3

×

144)

=

12h=

(

3

×

144)

=

h=

12

3

×144

=

h=

(

3

×

12)

=

h=

1.73×

12

=

h=

20.76cm

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Answer 2

Answer:

$288\sqrt3$

Step-by-step explanation:

Height = $\frac{\sqrt{3}}{2} \times(side)^2$ = $\frac{\sqrt{3}}{2} \times(24)^2$ = $\frac{\sqrt{3}}{2} \times576$ = $288 \times \sqrt{3}$ = $288\sqrt3$

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