Question

Find the length of the hypoteneois of square whose side is 16 cm

Answer 1

$\huge\underline{\underline{\mathfrak \orange{Answer}}}$

Lenght of hypotenuse is ${\bf \red{22.6cm}}$

$\huge\underline{\underline{\mathfrak \orange{Answer}}}$

$\large\underline{\underline{\sf Given:}}$

• Side of square is = 16cm

i.e perimeter (P) = 16cm

& Base (B) = 16cm

$\large\underline{\underline{\sf To\:Find:}}$

• Lenght of hypotenuse (H)

$\large\underline{\underline{\sf Formula\:Used:}}$

❏$\large{\boxed{\sf \blue{ H^2=P^2+B^2}}}$

$\implies{\sf H^2=(16)^2+(16)^2}$

$\implies{\sf H^2=256+256 }$

$\implies{\sf H^2=512}$

$\implies{\sf \red{H= 22.6cm}}$

Answer 2

Step-by-step explanation:

SIDE OF SQUARE is 16cm

PERIMETER =16

AND BASE=16

FIND THE LENGTH OF THE hypotenuse

${h}^{2} = {p}^{2} + {b}^{2}$

${h}^{2} = {16}^{2} + {16}^{2}$

${h }^{2} = 256 + 256$

${h }^{2} = 512$

$h = 22.6 \: cm$

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