Question

Find the length of the maximun long rod which can be placed in rectangular box of 5m * 12m

Answer 1

Given:

The rod has length 12m

The rod has breadth of 5m

We know that :

If l is the length of the rectangle and

If b is the breadth

and remember:

The diagonal is the longest rod that can be kept inside a figure.

length of diagonal = $\sqrt{l^2+b^2}$

Given:

l=12m

b=5m

So:

diagonal=$\sqrt{(12m)^2+(5m)^2}$

$\sqrt{144m^2+25m^2$

$\implies \sqrt{169m^2}$

$\implies 13m$

The length of the longest rod is 13m

Hope it helps.

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Answer 2

Hey dear here is your answer!!!!!

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The box is in the form of a rectangle and we can observe that the longest rod that can be put in the box is through the diagonals.

Let's name is vertices of the rectangle as A, B, C and D.

All the angles of a rectangle are 90° each.

So, we obtain a triangle ΔBDC right - angled at C.

We can simply apply the Pythagoras Theorem here to find the length of the rod which serves as Hypotenuse here.

Here it goes :-

(H)² = (P)² + (B)²

(H)² = (5)² + (12)²

(H)² = 25 + 144

(H)² = 169

H = √169

H = 13m

Therefore, the longest rod that can be fit in the box is 13m long !

*Am providing an image in attachment for your better understanding !*

❣️⭐ Hope it helps you dear...⭐⭐❣️❣️