Question

Find the length of the second diagonal of rhombus whose side 5cm and one of the diagonal is 6cm.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$Length\: of \: the \: \\second diagonal (d_{2})=8\:cm$

Step-by-step explanation:

$Let\:side \: of \: a \: Rhombus (a)= 5\:cm$

$and\: d_{1},d_{2} \: are \: diagonals$

$d_{1}= 6\: cm (given)$

$\frac{(d_{1})^{2}}{4}+\frac{(d_{2})^{2}}{4}=a^{2}$

$\implies \frac{6^{2}}{4}+\frac{(d_{2})^{2}}{4}=5^{2}$

$\implies \frac{36}{4}+\frac{(d_{2})^{2}}{4}=25$

$\implies 9+\frac{(d_{2})^{2}}{4}=25$

$\implies \frac{d_{2})^{2}}{4}=25-9$

$\implies \frac{(d_{2})^{2}}{4}=16$

$\implies (d_{2})^{2}=16\times 4$

$\implies d_{2}=\sqrt{16\times 4}$

$\implies d_{2}=4 \times 2$

$\implies d_{2}=8$

Therefore,

$Length\: of \: the \: \\second diagonal (d_{2})=8\:cm$

•••♪