Question

Find the length of the shortest altitude of a triangle with sides of lengths 10, 24, and 26.

Answer 1

Length = 10, 24, 36 
s = 10 + 24 + 36 / 2 = 70 / 2 = 35cm
√s(s-a)(s-b)(s-c) = √35 × 25 × 11 × (-1)
5√-385
1/2bh = -5√385
h = -5√385 × 18 = 1765 (approx.)