Find the length of the shortest altitude of a triangle with sides of lengths 10, 24, and 26.
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Length = 10, 24, 36
s = 10 + 24 + 36 / 2 = 70 / 2 = 35cm
√s(s-a)(s-b)(s-c) = √35 × 25 × 11 × (-1)
5√-385
1/2bh = -5√385
h = -5√385 × 18 = 1765 (approx.)
s = 10 + 24 + 36 / 2 = 70 / 2 = 35cm
√s(s-a)(s-b)(s-c) = √35 × 25 × 11 × (-1)
5√-385
1/2bh = -5√385
h = -5√385 × 18 = 1765 (approx.)
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