Question

Find the length of the side of a square field of area7744m². Also find its perimeter.

Answer 1

Answer:

⋆ DIAGRAM :

$\setlength{\unitlength}{1.5cm}\begin{picture}(8,2)\thicklines\put(7.7,3){\large{A}}\put(8.35,2){\bf{Area of Square}}}\put(7.7,1){\large{B}}\put(8.7,1.6){\bf{\large{7744 m^\bf2 }}}\put(10.6,1){\large{C}}\put(8,1){\line(1,0){2.5}}\put(8,1){\line(0,2){2}}\put(10.5,1){\line(0,3){2}}\put(8,3){\line(3,0){2.5}}\put(10.6,3){\large{D}}\end{picture}$

$\rule{170}{1}$

$\underline{\bigstar\:\textsf{Side of the Square :}}$

$:\implies\tt Area = (Side)^2\\\\\\:\implies\tt 7744\:m^2=(Side)^2\\\\\\:\implies\tt \sqrt{7744\:m^2}=Side\\\\\\:\implies\tt \sqrt{(88\:m \times 88\:m)}=Side\\\\\\:\implies\underline{\boxed{\tt Side = \textsf{\textbf{88\:m}}}}$

$\rule{170}{2}$

$\underline{\bigstar\:\textsf{Perimeter of the Square :}}$

$\dashrightarrow\tt\:\: Perimeter=4 \times Side\\\\\\\dashrightarrow\tt\:\: Perimeter=4 \times 88\:m\\\\\\\dashrightarrow\:\:\underline{\boxed{\tt Perimeter=\textsf{\textbf{352\:m}}}}$

Answer 2

Given

$\bold{ Area \ of \ the \ square \ field} = 7744 \ m^{2}$

SOMETHING YOU NEED TO REMEMBER

$\boxed{\bold{Area \ of \ a \ square = side * side}}\\\boxed{\bold{Perimeter \ of \ the \ square = 4 * sides}}$

Let each side of the square be x.

$=> x^{2} = 7744\\=> x = 88$

Therefore, each side of the square measures 88 m.

$\bold{Perimeter \ of \ the \ square} = 4 * side$

                                           $= 4 * 88$

                                           $=\boxed{\boxed{\bold{ 352 \ m}}}$