Question

Find the length of the string of the flying kite which is at an angle of 60° from the ground and 75 meters above the ground​

Answer 1

✬ String = 86.6 m ✬

Step-by-step explanation:

Given:

• Angle of elevation made by kite is 60°.
• Distance of kite above the ground is 75 m.

To Find:

• What is the length of string ?

Solution: Let in right angled triangle at B ,

• AB = Distance of kite from ground.
• BC = Ground
• AC = String

Now, in ∆ABC ,

• AB = Perpendicular
• BC = Base
• AC = Hypotenuse
• ∠ABC = 90°

$\implies{\rm }$ sinθ = Perpendicular/Hypotenuse

$\implies{\rm }$ sinC = AB/AC

$\implies{\rm }$ sin60° = 75/AC

$\implies{\rm }$ √3/2 = 75/AC

$\implies{\rm }$ AC√3 = 75(2)

$\implies{\rm }$ AC√3 = 150

$\implies{\rm }$ AC = 150/√3

$\implies{\rm }$ AC = 150/1.73

$\implies{\rm }$ AC = 86.6

Hence, the length of string of kite is of 86.6 m.

Answer 2

★ Refer to the attachment for diagram ★

Given ,

The kite is flying at an angle of 60 from the ground

The distance b/w kite and ground is 75 m

In Δ ABC ,

$: \mapsto \tt \sin(60) = \frac{60}{AB}$

$: \mapsto \tt \frac{ \sqrt{3} }{2} = \frac{75}{AB}$

$: \mapsto \tt AB = \frac{150}{ \sqrt{3} }$

$: \mapsto \tt AB = 50 \sqrt{3}$

$: \mapsto \tt AB = 86.6 \: \: m$

★ The length of string of kite is 86.6 m