find the lenth of a diagonal of a rectangle of a lenth 16 m and width 12 m
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diagnol of rectangle =√l^2+b^2
l= 16
b=12
diagnol =√16^2+12^2
=√256+144=√400=20
thus diagnol = 20 cm
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Answered by
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By Pythagoras Theorem
H² = B² + P²
H² = 16² + 12²
H² = 256 + 144
H² = 400
H = 20
Hence , length of the diagonal is 20 meter
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