Question

find the polynomial equation whoses roots are 3,2,1+i and 1-i.ans fast immediately breif explanation needed​

Answer 1

Step-by-step explanation:

(x - 2 - 3i)(x - 2 + 3i)(x - 1 - i)(x - 1 + i) = 0

((x - 2)^2 - (3i)^2)((x - 1)^2 - i^2) = 0

((x - 2)^2 - (9i^2))((x - 1)^2 -(-1)) = 0

((x - 2)^2 + 9)(x^2 - 2x + 1 + 1) = 0

(x^2 - 4x + 4 + 9)(x^2 - 2x + 2) = 0

(x^2 - 4x + 13)(x^2 - 2x + 2) = 0

x^4 - 2x^3 + 2x^2 - 4x^3 + 8x^2 - 8x + 13x^2 - 26x + 26 = 0

x^4 - 6x^3 + 23x^2 - 34x + 26 = 0