Find the letral surface area and total surface area of a cubiod whose length, breath and height is 20cm,10cm and 40cm
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l= 20cm
b= 10cm
h= 40cm
lateral surface area of cuboid=2h(l+b)
=2×40(20+10)
=80(30)
=2400cm
Total surface area=2(lb+bh+hl)
=2(20×10 + 10×40 + 40×20)
=2(200+400+800)
=2(1200)
=2400cm
b= 10cm
h= 40cm
lateral surface area of cuboid=2h(l+b)
=2×40(20+10)
=80(30)
=2400cm
Total surface area=2(lb+bh+hl)
=2(20×10 + 10×40 + 40×20)
=2(200+400+800)
=2(1200)
=2400cm
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