Question

find the letterd angle in this figure​

Answer 1

Answer:

Step-by-step explanation:

EDA=63 DEGREES (AS AF=AD)

EAD=180-63-63=54 DEGREES

CAB=EAD=54 DEGREES(VERTICALLY OPPOSITE)

CBA=X(CA=CB)

NOW,

X+X+54=180

2X=126

X=63 DEGREES

PLZ PLZ MARK BRAINLIEST

Answer 2

Hey there!

Answer:

63°

Step-by-step explanation:

Given,

∠E = 63°

Here, ΔDAE is isosceles Δ.  (2 sides are equal)

∠E = ∠D (base ∠s of isosceles Δ are equal)

∠E + ∠D + ∠DAE = 180° ( angle sum property)

63° + 63° + ∠DAE = 180°

∠DAE = 180 - 63 - 63

∠DAE = 54°

Now,

∠BAC = ∠DAE = 54°   (vertically opp. ∠s)

Again,

ΔBAC is isosceles Δ.  (2 sides are equal)

∠C = ∠E = x°    (base ∠s of isosceles Δ are equal)

Then,

∠B + ∠C + ∠BAC = 180°  (angle sum property)

x + x +54 = 180

2x = 180 - 54

x = 126 / 2

x = 63°

Hope It helps You!