Question

find the lettered angle​

Answer 1

Answer:

A=90 B=30 D=60 is answer

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

In ∆ACD,

angle ADC = angle ACD ( isosceles ∆ theorem)

angle ADC = 2x ........

angle ACB= angle ADC+ angle ACD...(exterior angle property)

angle ACB = 2x + 2x

= 4x .....(¡)

In ∆ABC,

angle ABC = angle ACB....(isosceles ∆ theorem)

angle ABC = 4x .....(¡¡)

By angle sum property,

In ∆ABC,

angle BAC + ABC + ACB = 180°

x +4x + 4x =180°

5x = 180°

x = 36°

angle BAC = 36°

angle CAD = 2x = 72°

angle BAD = 36° + 72° = 108°