Question

Find the lettered angles in each case​

Answer 1

Answer:

<a+<b+<c = 180°. ( measure of triangle= 180°)

50+90+<c = 180

<c = 180-140 = 40°

<x+<e+<c= 180°(measure of triangle= 180)

d+100+40=180

d+140=180

<x= 40°

Answer 2

Step-by-step explanation:

Solution :-

From the given figure,

In ∆ ABC ,

∠CAB = 50°

∠ABC = 90°

We know that

The sum of the three interior angles in a triangle is 180°

=> ∠CAB + ∠ABC + ∠BCA = 180°

=> 50° + 90° + ∠ BCA = 180°

=> 140° + ∠ BCA = 180°

=> ∠ BCA = 180° - 140°

=> ∠ BCA = 40°

And

In ∆ EDC ,

∠CED = 100°

∠EDC = x°

∠BCA = ∠DCE = 40°

We know that

The sum of the three interior angles in a triangle is 180°

=> ∠CED + ∠EDC + ∠ DCE= 180°

=> 100° + x° + 40° = 180°

=> 140° + x° = 180°

=> x° = 180° - 140°

=> x° = 40°

Answer :-

The value of x is 40°

Used Property:-

Angle Sum Property:-

The sum of the three interior angles in a triangle is 180°