find the limiting value of Lim x tends to 0 (x.lnx)
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limx→0(xln(x)+1)
limx→0(xln(x))+limx→01
The second limit belongs to a constant function, hence it will always give 1 for every value of x.
But the first limit looks more complex than the second one, since it not only has a ln(x) as denominator, but also ln(0)=UNDEFINED. So, in order to find a legit solution, we use a method named L'Hôpital's rule, where you take derivatives of both nominator and denominator one by one and then continue to find the limits.
limx→0(xln(x))
L’Hopital’s rule,
limx→011x
limx→0x=0
We also had a constant limit of value 1, as when we add two of these limits,
1+0=1
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