Find the locus of the foot of the perpendicular from the origin to a variable straight line which always
passes through a fixed point (a, b).
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Given:
Variable straight line which always passes through a fixed point (a, b).
To Find:
The locus of the foot of the perpendicular from the origin to the variable straight line
Solution:
Let A ( p , q ) be the foot of the perpendicular from the origin to the line.
Then line joining origin and the A ( p,q ) will be perpendicular to the line.
- Slope of line x slope of OA = -1
Now,
- Slope of the line = (q - b)/( p - a)
- Slope of OA = (q - 0 )/ (p - 0)
Applying the condition,
- (q - b )/( p -a ) x q / p = -1
- q² - qb = - 1 ( p² -pa )
- p² - pa + q² -pb = 0
- ( p , q ) can vary as ( x, y )
Therefore locus of the foot of the perpendicular from the origin to the variable straight line x² + y² -ax - by = 0
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