Math, asked by devichary9, 9 months ago

Find the log³³√2x⁵?​

Answers

Answered by kadalibullamma4832
0

Answer:

Firstly, let #y=\sqrtsin(2x)#

and let #u=sin(2x)#

this means #y=u^{\frac{1}{2}}#

Therefore #\frac{dy}{dx}=\frac{dy}{du}*\frac{du}{dx}#

#\frac{dy}{dx}=\frac{1}{2}u^{-\frac{1}{2}} * 2cos(2x)#

Which goes to

#\frac{dy}{dx}=\frac{cos2x}{sqrt{u}#

bring back #u=sin2x#

to get

#\frac{dy}{dx}=\frac{cos2x}{sqrt{sin2x}}#

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