Find the long division H.C.F 256,442and 940
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Step-by-step explanation:
Start by dividing 940 by 658. If divided correctly, the remainder would be 282. Then divide 658 by 282, remainder comes 94. Then divide 282 by 94, and they exactly divide with remainder 0. then, next, divide 1128 by 9 in a seperate part. The remainder is 0.
Hence, H.C.F. of the given numbers is 94.
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Answer:
To Find: the HCF of 3 Numbers 256,442 and 940
Find the product of its prime factors of 256:
256=2×2×2×2×2×2×2×2
256=2⁸
Find the product of its prime factors of 442:
442=2×13×17
Find the product of its prime factors of 940:
940=2×2×5×47
940=2²×5×47
Find the HCF of the 3 numbers:
256=2⁸
442=2×13×17
940=2²×5×47
HCF is the common factor among the three numbers
=HCF=2
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