Math, asked by rikininga2017, 1 year ago

find the longest no. which divides 615 and 963 leaving remainder 6 in each case

answer quickly

Answers

Answered by shreyadubey2
2
615-6=609
963-6= 957

take L.cm of 609 and 957
I hope it's help u....
THANKS........
..
Answered by Panzer786
5
Hiii friend,


615 - 6 = 609

And,


963 - 6 = 957

Prime factorisation of 609 = 3 × 7 × 29

Prime factorisation of 957 = 3 × 11 × 29

HCF of 609 and 957 = 3 × 29 = 87

Therefore,

Required Number = HCF(609,957) = 87


HOPE IT WILL HELP YOU..... :-)
Similar questions