find the longest no. which divides 615 and 963 leaving remainder 6 in each case
answer quickly
Answers
Answered by
2
615-6=609
963-6= 957
take L.cm of 609 and 957
I hope it's help u....
THANKS........
..
963-6= 957
take L.cm of 609 and 957
I hope it's help u....
THANKS........
..
Answered by
5
Hiii friend,
615 - 6 = 609
And,
963 - 6 = 957
Prime factorisation of 609 = 3 × 7 × 29
Prime factorisation of 957 = 3 × 11 × 29
HCF of 609 and 957 = 3 × 29 = 87
Therefore,
Required Number = HCF(609,957) = 87
HOPE IT WILL HELP YOU..... :-)
615 - 6 = 609
And,
963 - 6 = 957
Prime factorisation of 609 = 3 × 7 × 29
Prime factorisation of 957 = 3 × 11 × 29
HCF of 609 and 957 = 3 × 29 = 87
Therefore,
Required Number = HCF(609,957) = 87
HOPE IT WILL HELP YOU..... :-)
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