find the lower bound for the following lengths: a) 40 cm measured to the nearest cm b) 82.8 cm measured to the nearest tenth of a cm
Answers
Step-by-step explanation:
To calculate upper and lower bounds we can divide the degree by 2 (half) and add to the rounded value for upper bound but subtract for the lower bound.
- Given 40 cm measured to the nearest 1 cm.
- Now 1 cm / 2 = 0.5 cm
- So lower bound will be 40 – 0.5 = 39.5 cm
- We know that the Lower bound is the smallest value that is rounded to the estimated value.
- Given 82.8 cm measured to the nearest tenth of a cm
- Now degree is nearest 10 th place or 10 cm
- So 10 / 2 = 5 cm
- Lower bound = 82.8 – 5 = 82.3 cm
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Given:
a) 40 cm measured to the nearest cm b) 82.8 cm measured to the nearest tenth of a cm
To find:
Find the lower bound for the above lengths
Solution:
The lower bound is the smallest value that would round up to the estimated value.
The upper bound is the smallest value that would round up to the next estimated value.
a) 40 cm measured to the nearest cm
The degree of accuracy is to the nearest 1 cm.
1/2 = 0.5 cm
Lower bound for 40 cm = 40 - 0.5 = 39.5 cm
The tenth place is the first number after the decimal. If it is asked round to the nearest tenth, then the result should only have one number after the decimal
b) 82.8 cm measured to the nearest tenth of a cm
The degree of accuracy is to the nearest tenth of a cm.
1/10 = 0.1 cm
Lower bound for 82.8 cm = 82.8 - 0.1 = 82.7 cm