Question

find the lowest five digit number which when divided by 12,18,21 and 28 leaves no remainder in each case ​

Answer 1

Step-by-step explanation:

LCM (12,18,21,28) = 252

Lowest five digit number = 10000

10000/ 252 gives 172 as remainder

252 - 172 = 80

10000 + 80 = 10080

ie, if 10080 when divided with any of 12,18,21,28, gives 0 as remainder

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Answer 2

Answer:

/begin{document}

lcm of 12,18,21,28 is 252 //

now least no of 5 digit =10000 //

dividing 10000 by 252 we get the remainder as 172 //

now 252-172=80 //

because we have to find least five digit no that is exactly divisible by 252 //

so (10000+80)=10080 is the least 5 digit no that is divided by 12,18,31,28 and leaves no remainder//

/end{document}