Question

Find the lowest number 200 and 500 which leaves a remainder of 3 divided by 8 10 12 and 30

Answer 1

Answer:

Step-by-step explanation:

243 is the lowest number between 200 and 500 which a remainder of 3 in each case when divided by 8 ,10,12,30

The lowest number between 200 And 500 which When divided by 8,10,12,30 leaving remainder 3 will be

LCM of these + 3

8=2³

10=2×5

12=2²×3

30=2×3×5

LCM=2³×3×5=120

we need to find number between 200 and 500

so 120×2=240

required number =240+3=243