In an event A and B where P(A) >0 and P(B)> 0 and P(A)+P(B)-P(A intersection B) = P(A) then 1. P(A/B)=1 2. P(B/A)=1 3. P(A/B)=0 4. P(B/A)=0
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E, will die and B will live E, B will die and Awill live So, required probability=P(E)- P(E) = p(1–q)+q(1-p) = p + q – 2pq. ... S = {1,2,3,4,5,6} x {1,2,3,4,5,6}
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