Question

Find the magnetic induction at a point distant 10 cm on the axis of a short bar magnet of moment 0.2 Am^2.​

Answer 1

Explanation:

Correct option is

C

7

×10

−7

T

Magnetic field due to a bar magnet of magnetic dipole moment M at a

distance from it in a direction θ with its magnetic moment is

B=

4π

μ

0

.

r

3

M

(3cos

2

θ+1)

where,

4π

μ

0

=10

−7

Tm/A

Given,

M=2Am

2

r=1m

θ=60

0

⇒B=(10

−7

Tm/A)×

(1m)

3

2Am

2

×

(

4

3

+1)

=

7

×10

−7

T

Answer 2

please mark the brainly