Question

the sum of the age of father and his son is 48 years . six years ago , the fathees age was five time the age of the his son. the present age of son is?​

Answer 1

see the picture 1st and then see the step by step explanation actually I had no space in my book so

Step-by-step explanation:

Substituting this value of 

yy

 in the equation 

(1)(1)

, we get

⇒x+x+245=48⇒5x+x+245=48⇒6x+245=48⇒x+x+245=48⇒5x+x+245=48⇒6x+245=48

Multiplying the above equation by 5 on both sides, we get

⇒6x+24=48×5⇒6x+24=240⇒6x+24=48×5⇒6x+24=240

Subtracting the above equation by 24 on each side, we get

⇒6x+24−24=240−24⇒6x=216⇒6x+24−24=240−24⇒6x=216

Dividing the above equation by 6 into both sides, we get

⇒6x6=2166⇒x=36⇒6x6=2166⇒x=36

Substituting the above value of 

xx

 in the equation 

(1)(1)

, we get

36+y

Answer 2

Step-by-step explanation:

SEE THE ABOVE ANS.The last step 36+12 is for verification no need to write