Question

Find the magnitude and direction in a semi circle of radius 0.5 cm carrying a current of 2A which placed in a uniform magnetic field 0.3T

Answer 1

Answer: 0.06 N

you mean force on a semicircle ? correct.

Explanation:

this will be solved using an integral

of F over Delta s from o to pi/ 2

Magnetic force on the semicircular wire, Fmag =i∫(dl ×B )=iB∫dl =iB(2r)=2iBr(−r^)

where r is the radius of the semi circular loop.

F Net =2B I R= 0.6x 2x 5/100= 0.06 N .

Direction Is Perpendicular to Diameter of Semi Loop, pointing in Radial outwards direction