Question

find the magnitude and direction of the resultant V1 3m/s acting towards East and v2 5√2 m/s acting towards north east​

Answer 1

Explanation:

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Class 11>>Physics>>Motion in a Straight Line>>Acceleration>>A particle moves towards east with veloc

Question

A particle moves towards east with  velocity 5m/s. After 10 seconds its direction changes towards north with same velocity. The average acceleration of the particle is 

A

Zero

B

21m/s2N−W

C

21m/s2N−E

D

21m/s2S−W

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Solution

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Correct option is B)

correct option is B.

Intial velocity=v1=5m/seast wards  

                                 

then after time t=10sec              

                                       

v2=5m/s north wards                                    

                                                                

δv=V12+V22

         =25+25

         =52

acceleration a=timeveloci

hi nandana

how are u