find the magnitude and direction of the unknown currents in figure 1. Given i; = 10A,
i2 = 6A, is = 4A.
b
R2
R1
i5
17
R5
il a
14
C с
R3
R4
i6
E
value of i3,i4,i6i7
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Answer:
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Explanation:
For the loop containing the 18-V source
−18+3×2+8I1 = 0.
Hence, I1 = 1.5 A.
KCL at node a gives
3−1−I1 −I2 = 0
I2 = 2−I1 = 2−1.5 = 0.5 A.
KCL at node b gives
1+I2 −I3 = 0
I3 = 1+I2 = 1+0.5 = 1.5 A.
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