Question

find the magnitude forA vector =5i-2j+3k

Answer 1

hope it helps you out

Answer 2

The magnitude of the vector = √38 units

Given :

The vector $\vec{A} = 5 \hat{i} - 2\hat{j} + 3 \hat{k}$

To find :

The magnitude of the vector

Solution :

Step 1 of 2 :

Write down the given vector

Here the given vector is

$\vec{A} = 5 \hat{i} - 2\hat{j} + 3 \hat{k}$

Step 2 of 2 :

Calculate magnitude of the vector

The magnitude of the vector

$\displaystyle = |\vec{A}|$

$= |5 \hat{i} - 2\hat{j} + 3 \hat{k}|$

$\displaystyle \sf = \sqrt{ {(5)}^{2} + {( - 2)}^{2} + {( 3)}^{2} } \: \: units$

$\displaystyle \sf = \sqrt{ 25 + 4 + 9 } \: \: units$

$\displaystyle \sf = \sqrt{ 38 } \: \: units$

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