Find the magnitude of a charge that can be moved from inifinity to a point in an electric field where the potential is 20 V, by spending 600 J of work.
Answers
Answered by
2
Answer:
I hope (580)
Explanation:
600 j
20v
=580
Answered by
33
Answer:
Given, electric potential, V = 20 V
Work done, W = 600 J.
We know that, W = V q
Therefore, q = W/V = 600/20 = 30 C.
Hence, 30 C is the magnitude.
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