Question

find the magnitude of an angle 2/3 of its supplement

Answer 1

let the angle be 2x
given that the angle is 2/3 of its supplement
so we can say that
2x +3x = 180°
5x=180°
x= 36°
the angle is 2x
therefore 2*36° =72°

Answer 2

let the angle is x and it's supplement is 2/3(180-x)

x = 2/3(180 - x)

3x = 360 - 2x

5x = 360

x = 72°


Hence the angle is 72°

Thanks