Question

find the magnitude of an angle which is 2 by 3 of its supplement

Answer 1

Let the angle be θ 
then its supplement be (180 - θ) 
ATQ 
θ = 2/3(180 - θ)
3θ = 360 - 2θ 
5θ = 360 
θ   = 72 °
its supplement 
180 - θ = 108°

Answer 2

Let the supplement be 'x'
Then the angle is 2/3xA/Q --->x + 2/3x = 180
(3x+ 2x)/3 = 180
5x = 540
x = 108°The angle is - 2/3 x = 2/3 x 108 = 72°
Hope This Helps You!