Question

Find the magnitude of an isolated point charge ,if electric potential at 10 cm from change to be 100 v

Answer 1

d = 10cm.   V = 100 volt

$V = \frac{1} {4πε} \frac{q}{d}$

100 = 9 X 10⁹ q/ 10⁻¹

q = 1.11 X 10⁻⁹

q = 1.11 nC