Question

find the magnitude of an isolated point charge, if the electric potential from 10 m is 100V.

Answer 1

The magnitude of the isolated point charge is  1.11×10⁻⁷ C.

Given the value of electric potential (V) = 100V

The distance of the isolated point charge from the potential (r) is = 10m.

We know the magnitude of point charge, denoted by Q is:

Q = (4Пε₀r)V

Putting the values of 4Пε₀ = 1.11×10⁻¹⁰

r = 10m,

V = 100 V

We get:

Q = (1.11×10⁻¹⁰ × 10 × 100) = 1.11×10⁻⁷ C

This is the value of charge.