Question

find the magnitude of average acceleration of the tip of minute hand of clock (length =20cm) when it rotate by an angle of π/2​

Answer 1

Answer:

bhai/behen jaha maine arrow diya hai waha 10 ka jagah bas 20 laga lena or multiple kar dena

Answer 2

Answer:

Average acceleration of the minute hand: $a=6.09*10^{-7}m/s$

Explanation:

Length of the minute hand clock = 20cm = 0.2m

Angle $\frac{\pi}{2}radians = 90^o$

Time taken by minute hand to complete $90^o$ in the clock = 15 minutes = 15x60 seconds = 900sec.

Therefore, the angular velocity of the minute hand of the clock is,

$w=\frac{\frac{\pi}{2}}{900} rad/s$

$w=\frac{\pi}{1800} rad/s$

The magnitude of the acceleration is given by the formula,

$|a|=w^2r$

where, $a$ denotes acceleration,

and $r$ denotes radius(length of minute hand to the tip).

Therefore, $a=(\frac{\pi}{1800} )^2 *(20*10^{-2})$

Required average acceleration of the minute hand: $a=6.09*10^{-7}m/s$

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