find the magnitude of average accleration of the tip of second hand of length 10 cm during 10 seconds....
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The seconds hand clock is 10 cm long .it goes around once every 10 s
(A) what is the average speed of the tip of the second hand?
(b) what is the distance travelled by the tip in the 10 sec?
(C)what is the average velocity during times it makes one revolution?
take pi=3.14.
ans ( 1.05cm/s,10.5 cm,zero)
(a) Average speed of the tip of the second hand clock is given as,
Total distance travelled / total time taken
=2πrt=2×3.14×1060(second hand completes one revolution in 60 s)So, average speed=1.05 cm/s
(b) Distance travelled in the 10 seconds=Speed×time=1.05×10=10.5 cm
(c) Average velocity=Total displacementtimeOn the completion of one revolution, Displacement=Final position−Initial position=0So,average velocity=0
I hope this is helpful for you....
The seconds hand clock is 10 cm long .it goes around once every 10 s
(A) what is the average speed of the tip of the second hand?
(b) what is the distance travelled by the tip in the 10 sec?
(C)what is the average velocity during times it makes one revolution?
take pi=3.14.
ans ( 1.05cm/s,10.5 cm,zero)
(a) Average speed of the tip of the second hand clock is given as,
Total distance travelled / total time taken
=2πrt=2×3.14×1060(second hand completes one revolution in 60 s)So, average speed=1.05 cm/s
(b) Distance travelled in the 10 seconds=Speed×time=1.05×10=10.5 cm
(c) Average velocity=Total displacementtimeOn the completion of one revolution, Displacement=Final position−Initial position=0So,average velocity=0
I hope this is helpful for you....
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